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# Test case for `icebox_asc2hlc' and `icebox_hlc2asc': Does conversion
# from LUT strings to logic expressions and back work correctly?
# Copyright (C) 2017 Roland Lutz
#
# Permission to use, copy, modify, and/or distribute this software for any
# purpose with or without fee is hereby granted, provided that the above
# copyright notice and this permission notice appear in all copies.
#
# THE SOFTWARE IS PROVIDED "AS IS" AND THE AUTHOR DISCLAIMS ALL WARRANTIES
# WITH REGARD TO THIS SOFTWARE INCLUDING ALL IMPLIED WARRANTIES OF
# MERCHANTABILITY AND FITNESS. IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR
# ANY SPECIAL, DIRECT, INDIRECT, OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES
# WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN AN
# ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING OUT OF
# OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS SOFTWARE.
import sys
import icebox
from icebox_asc2hlc import lut_to_logic_expression
from icebox_hlc2asc import logic_expression_to_lut
def main():
sys.stderr.write("testing conversion from LUT strings "
"to logic expressions and back")
for i in range(65536):
if i % 4096 == 0:
sys.stderr.write(".")
sys.stderr.flush()
lut = bin(i)[2:].zfill(16)
s = lut_to_logic_expression(lut, ('a', 'b', 'c', 'd'))
l = logic_expression_to_lut(s, ('a', 'b', 'c', 'd'))
if l != lut:
sys.stderr.write("\nERROR at LUT = %s\n" % lut)
sys.stderr.write("stringified = %s\n" % s)
sys.stderr.write("resulting LUT = %s\n" % l)
sys.exit(1)
sys.stderr.write("\n")
if __name__ == '__main__':
main()
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