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# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or
# implied.
# See the License for the specific language governing permissions and
# limitations under the License.
import os.path
def load_vectors_from_file(filename, loader):
base = os.path.join(
os.path.dirname(__file__), "hazmat", "primitives", "vectors",
)
with open(os.path.join(base, filename), "r") as vector_file:
return loader(vector_file)
def load_nist_vectors(vector_data):
test_data = None
data = []
for line in vector_data:
line = line.strip()
# Blank lines, comments, and section headers are ignored
if not line or line.startswith("#") or (line.startswith("[")
and line.endswith("]")):
continue
if line.strip() == "FAIL":
test_data["fail"] = True
continue
# Build our data using a simple Key = Value format
name, value = [c.strip() for c in line.split("=")]
# COUNT is a special token that indicates a new block of data
if name.upper() == "COUNT":
test_data = {}
data.append(test_data)
continue
# For all other tokens we simply want the name, value stored in
# the dictionary
else:
test_data[name.lower()] = value.encode("ascii")
return data
def load_cryptrec_vectors(vector_data):
cryptrec_list = []
for line in vector_data:
line = line.strip()
# Blank lines and comments are ignored
if not line or line.startswith("#"):
continue
if line.startswith("K"):
key = line.split(" : ")[1].replace(" ", "").encode("ascii")
elif line.startswith("P"):
pt = line.split(" : ")[1].replace(" ", "").encode("ascii")
elif line.startswith("C"):
ct = line.split(" : ")[1].replace(" ", "").encode("ascii")
# after a C is found the K+P+C tuple is complete
# there are many P+C pairs for each K
cryptrec_list.append({
"key": key,
"plaintext": pt,
"ciphertext": ct
})
else:
raise ValueError("Invalid line in file '{}'".format(line))
return cryptrec_list
def load_openssl_vectors(vector_data):
vectors = []
for line in vector_data:
line = line.strip()
# Blank lines and comments are ignored
if not line or line.startswith("#"):
continue
vector = line.split(":")
vectors.append({
"key": vector[1].encode("ascii"),
"iv": vector[2].encode("ascii"),
"plaintext": vector[3].encode("ascii"),
"ciphertext": vector[4].encode("ascii"),
})
return vectors
def load_hash_vectors(vector_data):
vectors = []
key = None
msg = None
md = None
for line in vector_data:
line = line.strip()
if not line or line.startswith("#") or line.startswith("["):
continue
if line.startswith("Len"):
length = int(line.split(" = ")[1])
elif line.startswith("Key"):
"""
HMAC vectors contain a key attribute. Hash vectors do not.
"""
key = line.split(" = ")[1].encode("ascii")
elif line.startswith("Msg"):
"""
In the NIST vectors they have chosen to represent an empty
string as hex 00, which is of course not actually an empty
string. So we parse the provided length and catch this edge case.
"""
msg = line.split(" = ")[1].encode("ascii") if length > 0 else b""
elif line.startswith("MD"):
md = line.split(" = ")[1]
# after MD is found the Msg+MD (+ potential key) tuple is complete
if key is not None:
vectors.append((msg, md, key))
key = None
msg = None
md = None
else:
vectors.append((msg, md))
msg = None
md = None
else:
raise ValueError("Unknown line in hash vector")
return vectors
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