From 079641531492b0f5b87e08278aa229d047bea1e5 Mon Sep 17 00:00:00 2001 From: Vadim Berezniker Date: Fri, 17 Aug 2018 10:49:10 -0700 Subject: std references shouldn't be fully qualified --- googletest/docs/advanced.md | 8 ++++---- 1 file changed, 4 insertions(+), 4 deletions(-) diff --git a/googletest/docs/advanced.md b/googletest/docs/advanced.md index 0a92e524..3a097f1b 100644 --- a/googletest/docs/advanced.md +++ b/googletest/docs/advanced.md @@ -572,7 +572,7 @@ namespace foo { class Bar { // We want googletest to be able to print instances of this. ... // Create a free inline friend function. - friend ::std::ostream& operator<<(::std::ostream& os, const Bar& bar) { + friend std::ostream& operator<<(std::ostream& os, const Bar& bar) { return os << bar.DebugString(); // whatever needed to print bar to os } }; @@ -580,7 +580,7 @@ class Bar { // We want googletest to be able to print instances of this. // If you can't declare the function in the class it's important that the // << operator is defined in the SAME namespace that defines Bar. C++'s look-up // rules rely on that. -::std::ostream& operator<<(::std::ostream& os, const Bar& bar) { +std::ostream& operator<<(std::ostream& os, const Bar& bar) { return os << bar.DebugString(); // whatever needed to print bar to os } @@ -601,7 +601,7 @@ namespace foo { class Bar { ... - friend void PrintTo(const Bar& bar, ::std::ostream* os) { + friend void PrintTo(const Bar& bar, std::ostream* os) { *os << bar.DebugString(); // whatever needed to print bar to os } }; @@ -609,7 +609,7 @@ class Bar { // If you can't declare the function in the class it's important that PrintTo() // is defined in the SAME namespace that defines Bar. C++'s look-up rules rely // on that. -void PrintTo(const Bar& bar, ::std::ostream* os) { +void PrintTo(const Bar& bar, std::ostream* os) { *os << bar.DebugString(); // whatever needed to print bar to os } -- cgit v1.2.3